Base | Representation |
---|---|
bin | 10101111111001001100101… |
… | …00110000010111000110010 |
3 | 20100012010222112202201020022 |
4 | 22333210302212002320302 |
5 | 22314123324143411140 |
6 | 250455205415043442 |
7 | 13120056422306234 |
oct | 1277446246027062 |
9 | 210163875681208 |
10 | 48349295685170 |
11 | 14450903a50487 |
12 | 550a501370582 |
13 | 20c941bb69bac |
14 | bd2192c4c254 |
15 | 58ca21e600b5 |
hex | 2bf932982e32 |
48349295685170 has 16 divisors (see below), whose sum is σ = 87216699265920. Its totient is φ = 19297947822384.
The previous prime is 48349295685169. The next prime is 48349295685181. The reversal of 48349295685170 is 7158659294384.
48349295685170 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 48349295685094 and 48349295685103.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5221301600 + ... + 5221310859.
It is an arithmetic number, because the mean of its divisors is an integer number (5451043704120).
It is a 1-persistent number, because it is pandigital, but 2⋅48349295685170 = 96698591370340 is not.
Almost surely, 248349295685170 is an apocalyptic number.
48349295685170 is a deficient number, since it is larger than the sum of its proper divisors (38867403580750).
48349295685170 is a wasteful number, since it uses less digits than its factorization.
48349295685170 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10442612929.
The product of its (nonzero) digits is 522547200, while the sum is 71.
The spelling of 48349295685170 in words is "forty-eight trillion, three hundred forty-nine billion, two hundred ninety-five million, six hundred eighty-five thousand, one hundred seventy".
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