Base | Representation |
---|---|
bin | 100011001101111010011… |
… | …1111000100101001000011 |
3 | 122010201111212210102222022 |
4 | 1012123310333010221003 |
5 | 1113300304244200313 |
6 | 14143324353032055 |
7 | 1006460512433321 |
oct | 106336477045103 |
9 | 18121455712868 |
10 | 4840243350083 |
11 | 15a6810205979 |
12 | 6620a385562b |
13 | 29158237c29b |
14 | 12a3aa2dad11 |
15 | 85d8c302c08 |
hex | 466f4fc4a43 |
4840243350083 has 2 divisors, whose sum is σ = 4840243350084. Its totient is φ = 4840243350082.
The previous prime is 4840243349993. The next prime is 4840243350109. The reversal of 4840243350083 is 3800533420484.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4840243350083 - 220 = 4840242301507 is a prime.
It is a super-2 number, since 2×48402433500832 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4845243350083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2420121675041 + 2420121675042.
It is an arithmetic number, because the mean of its divisors is an integer number (2420121675042).
Almost surely, 24840243350083 is an apocalyptic number.
4840243350083 is a deficient number, since it is larger than the sum of its proper divisors (1).
4840243350083 is an equidigital number, since it uses as much as digits as its factorization.
4840243350083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1105920, while the sum is 44.
The spelling of 4840243350083 in words is "four trillion, eight hundred forty billion, two hundred forty-three million, three hundred fifty thousand, eighty-three".
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