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484113601 is a prime number
BaseRepresentation
bin11100110110101…
…111110011000001
31020201221112000101
4130312233303001
51442413113401
6120012122401
714665616626
oct3466576301
91221845011
10484113601
112292a6794
12116166401
13793b216a
144841c34d
152c77b101
hex1cdafcc1

484113601 has 2 divisors, whose sum is σ = 484113602. Its totient is φ = 484113600.

The previous prime is 484113563. The next prime is 484113611. The reversal of 484113601 is 106311484.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 307090576 + 177023025 = 17524^2 + 13305^2 .

It is a cyclic number.

It is not a de Polignac number, because 484113601 - 27 = 484113473 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 484113601.

It is not a weakly prime, because it can be changed into another prime (484113611) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 242056800 + 242056801.

It is an arithmetic number, because the mean of its divisors is an integer number (242056801).

Almost surely, 2484113601 is an apocalyptic number.

It is an amenable number.

484113601 is a deficient number, since it is larger than the sum of its proper divisors (1).

484113601 is an equidigital number, since it uses as much as digits as its factorization.

484113601 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 28.

The square root of 484113601 is about 22002.5816894291. The cubic root of 484113601 is about 785.2038639115.

The spelling of 484113601 in words is "four hundred eighty-four million, one hundred thirteen thousand, six hundred one".