Base | Representation |
---|---|
bin | 10110000101011110001011… |
… | …00101010100101011010011 |
3 | 20100221220122121000212012011 |
4 | 23002233011211110223103 |
5 | 22331203203042031233 |
6 | 251143051410043351 |
7 | 13141546252415032 |
oct | 1302570545245323 |
9 | 210856577025164 |
10 | 48566510111443 |
11 | 14524a39916955 |
12 | 5544621b79557 |
13 | 2113a57717bcc |
14 | bdc8bb2a8719 |
15 | 5934d68150cd |
hex | 2c2bc5954ad3 |
48566510111443 has 2 divisors, whose sum is σ = 48566510111444. Its totient is φ = 48566510111442.
The previous prime is 48566510111419. The next prime is 48566510111491. The reversal of 48566510111443 is 34411101566584.
48566510111443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 48566510111443 - 241 = 46367486855891 is a prime.
It is not a weakly prime, because it can be changed into another prime (48566510111843) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24283255055721 + 24283255055722.
It is an arithmetic number, because the mean of its divisors is an integer number (24283255055722).
Almost surely, 248566510111443 is an apocalyptic number.
48566510111443 is a deficient number, since it is larger than the sum of its proper divisors (1).
48566510111443 is an equidigital number, since it uses as much as digits as its factorization.
48566510111443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1382400, while the sum is 49.
The spelling of 48566510111443 in words is "forty-eight trillion, five hundred sixty-six billion, five hundred ten million, one hundred eleven thousand, four hundred forty-three".
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