Base | Representation |
---|---|
bin | 110111001101101110010001… |
… | …1101000111110011101011011 |
3 | 2100200121201021022111101011021 |
4 | 1232123130203220332131123 |
5 | 1002124214111412333124 |
6 | 4440534134340343311 |
7 | 204204405131416141 |
oct | 15633344350763533 |
9 | 2320551238441137 |
10 | 485671204808539 |
11 | 1308280017683a2 |
12 | 4657a3bb9a4b37 |
13 | 17acc7a1035119 |
14 | 87d087c863591 |
15 | 3b236513a27e4 |
hex | 1b9b723a3e75b |
485671204808539 has 2 divisors, whose sum is σ = 485671204808540. Its totient is φ = 485671204808538.
The previous prime is 485671204808443. The next prime is 485671204808597. The reversal of 485671204808539 is 935808402176584.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-485671204808539 is a prime.
It is not a weakly prime, because it can be changed into another prime (485671204608539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 242835602404269 + 242835602404270.
It is an arithmetic number, because the mean of its divisors is an integer number (242835602404270).
It is a 1-persistent number, because it is pandigital, but 2⋅485671204808539 = 971342409617078 is not.
Almost surely, 2485671204808539 is an apocalyptic number.
485671204808539 is a deficient number, since it is larger than the sum of its proper divisors (1).
485671204808539 is an equidigital number, since it uses as much as digits as its factorization.
485671204808539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 464486400, while the sum is 70.
The spelling of 485671204808539 in words is "four hundred eighty-five trillion, six hundred seventy-one billion, two hundred four million, eight hundred eight thousand, five hundred thirty-nine".
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