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48680793423 = 338920258341
BaseRepresentation
bin101101010101100110…
…011111010101001111
311122122122111112102000
4231111212133111033
51244144240342143
634210314203343
73342232626303
oct552546372517
9148578445360
1048680793423
1119711047689
129527123553
13478a66b812
1424db44dd03
1513edb5dbd3
hexb5599f54f

48680793423 has 16 divisors (see below), whose sum is σ = 72930031200. Its totient is φ = 32089210560.

The previous prime is 48680793391. The next prime is 48680793431. The reversal of 48680793423 is 32439708684.

It is not a de Polignac number, because 48680793423 - 25 = 48680793391 is a prime.

It is a super-3 number, since 3×486807934233 (a number of 33 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 48680793423.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (48680793433) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10126768 + ... + 10131573.

It is an arithmetic number, because the mean of its divisors is an integer number (4558126950).

Almost surely, 248680793423 is an apocalyptic number.

48680793423 is a deficient number, since it is larger than the sum of its proper divisors (24249237777).

48680793423 is a wasteful number, since it uses less digits than its factorization.

48680793423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20258439 (or 20258433 counting only the distinct ones).

The product of its (nonzero) digits is 6967296, while the sum is 54.

The spelling of 48680793423 in words is "forty-eight billion, six hundred eighty million, seven hundred ninety-three thousand, four hundred twenty-three".

Divisors: 1 3 9 27 89 267 801 2403 20258341 60775023 182325069 546975207 1802992349 5408977047 16226931141 48680793423