Base | Representation |
---|---|
bin | 100011011100111001011… |
… | …0000001010000100110111 |
3 | 122020210120012100010220120 |
4 | 1012321302300022010313 |
5 | 1114312203020443341 |
6 | 14210205154303023 |
7 | 1012010030564040 |
oct | 106716260120467 |
9 | 18223505303816 |
10 | 4872418140471 |
11 | 1609421020132 |
12 | 668382b87a73 |
13 | 29460c18a2ab |
14 | 12bb7d4dd8c7 |
15 | 86b21d19066 |
hex | 46e72c0a137 |
4872418140471 has 64 divisors (see below), whose sum is σ = 7903832506368. Its totient is φ = 2609839761408.
The previous prime is 4872418140451. The next prime is 4872418140479. The reversal of 4872418140471 is 1740418142784.
It is not a de Polignac number, because 4872418140471 - 26 = 4872418140407 is a prime.
It is a super-3 number, since 3×48724181404713 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4872418140479) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5855610 + ... + 6635736.
It is an arithmetic number, because the mean of its divisors is an integer number (123497382912).
Almost surely, 24872418140471 is an apocalyptic number.
4872418140471 is a deficient number, since it is larger than the sum of its proper divisors (3031414365897).
4872418140471 is a wasteful number, since it uses less digits than its factorization.
4872418140471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 780420.
The product of its (nonzero) digits is 1605632, while the sum is 51.
The spelling of 4872418140471 in words is "four trillion, eight hundred seventy-two billion, four hundred eighteen million, one hundred forty thousand, four hundred seventy-one".
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