Base | Representation |
---|---|
bin | 100011011110110000010… |
… | …0100110001100111110011 |
3 | 122021011212021012211020112 |
4 | 1012331200210301213303 |
5 | 1114343340440243011 |
6 | 14212105125531535 |
7 | 1012210640143442 |
oct | 106754044614763 |
9 | 18234767184215 |
10 | 4876408134131 |
11 | 161008929a456 |
12 | 6690b7273bab |
13 | 294ac69b72a1 |
14 | 12c03b3aad59 |
15 | 86ca726458b |
hex | 46f609319f3 |
4876408134131 has 2 divisors, whose sum is σ = 4876408134132. Its totient is φ = 4876408134130.
The previous prime is 4876408134121. The next prime is 4876408134137. The reversal of 4876408134131 is 1314318046784.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4876408134131 - 242 = 478361623027 is a prime.
It is a super-2 number, since 2×48764081341312 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 4876408134131.
It is not a weakly prime, because it can be changed into another prime (4876408134137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2438204067065 + 2438204067066.
It is an arithmetic number, because the mean of its divisors is an integer number (2438204067066).
Almost surely, 24876408134131 is an apocalyptic number.
4876408134131 is a deficient number, since it is larger than the sum of its proper divisors (1).
4876408134131 is an equidigital number, since it uses as much as digits as its factorization.
4876408134131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1548288, while the sum is 50.
The spelling of 4876408134131 in words is "four trillion, eight hundred seventy-six billion, four hundred eight million, one hundred thirty-four thousand, one hundred thirty-one".
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