Base | Representation |
---|---|
bin | 100011011110110000010… |
… | …0111110100111100000011 |
3 | 122021011212022201110122202 |
4 | 1012331200213310330003 |
5 | 1114343341141343042 |
6 | 14212105155023415 |
7 | 1012210650015032 |
oct | 106754047647403 |
9 | 18234768643582 |
10 | 4876408934147 |
11 | 1610089796523 |
12 | 6690b759ab6b |
13 | 294ac6c0747a |
14 | 12c03b538719 |
15 | 86ca7371632 |
hex | 46f609f4f03 |
4876408934147 has 2 divisors, whose sum is σ = 4876408934148. Its totient is φ = 4876408934146.
The previous prime is 4876408934129. The next prime is 4876408934179. The reversal of 4876408934147 is 7414398046784.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4876408934147 - 212 = 4876408930051 is a prime.
It is not a weakly prime, because it can be changed into another prime (4876408930147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2438204467073 + 2438204467074.
It is an arithmetic number, because the mean of its divisors is an integer number (2438204467074).
Almost surely, 24876408934147 is an apocalyptic number.
4876408934147 is a deficient number, since it is larger than the sum of its proper divisors (1).
4876408934147 is an equidigital number, since it uses as much as digits as its factorization.
4876408934147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 130056192, while the sum is 65.
The spelling of 4876408934147 in words is "four trillion, eight hundred seventy-six billion, four hundred eight million, nine hundred thirty-four thousand, one hundred forty-seven".
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