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4877080118593 is a prime number
BaseRepresentation
bin100011011111000100010…
…1000001100010101000001
3122021020121002200011121221
41012332020220030111001
51114401230002243333
614212255532515041
71012233410003014
oct106761050142501
918236532604557
104877080118593
1116103a3644311
1266926431ba81
13294ba2c97a27
1412c0a273137b
1586ce6250d2d
hex46f88a0c541

4877080118593 has 2 divisors, whose sum is σ = 4877080118594. Its totient is φ = 4877080118592.

The previous prime is 4877080118557. The next prime is 4877080118597. The reversal of 4877080118593 is 3958110807784.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4152090878224 + 724989240369 = 2037668^2 + 851463^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4877080118593 is a prime.

It is a super-2 number, since 2×48770801185932 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4877080118597) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2438540059296 + 2438540059297.

It is an arithmetic number, because the mean of its divisors is an integer number (2438540059297).

Almost surely, 24877080118593 is an apocalyptic number.

It is an amenable number.

4877080118593 is a deficient number, since it is larger than the sum of its proper divisors (1).

4877080118593 is an equidigital number, since it uses as much as digits as its factorization.

4877080118593 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13547520, while the sum is 61.

The spelling of 4877080118593 in words is "four trillion, eight hundred seventy-seven billion, eighty million, one hundred eighteen thousand, five hundred ninety-three".