Base | Representation |
---|---|
bin | 10110001011111001011010… |
… | …10111010011101101000011 |
3 | 20101202000112102222221221011 |
4 | 23011330231113103231003 |
5 | 22343312334404200003 |
6 | 251432323531541351 |
7 | 13163523432536431 |
oct | 1305745527235503 |
9 | 211660472887834 |
10 | 48787294600003 |
11 | 145aa636a12a23 |
12 | 557b37a2ba857 |
13 | 212b811ac350b |
14 | c0946391dd51 |
15 | 59910981646d |
hex | 2c5f2d5d3b43 |
48787294600003 has 2 divisors, whose sum is σ = 48787294600004. Its totient is φ = 48787294600002.
The previous prime is 48787294599983. The next prime is 48787294600013. The reversal of 48787294600003 is 30000649278784.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 48787294600003 - 25 = 48787294599971 is a prime.
It is a super-2 number, since 2×487872946000032 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (48787294600013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24393647300001 + 24393647300002.
It is an arithmetic number, because the mean of its divisors is an integer number (24393647300002).
Almost surely, 248787294600003 is an apocalyptic number.
48787294600003 is a deficient number, since it is larger than the sum of its proper divisors (1).
48787294600003 is an equidigital number, since it uses as much as digits as its factorization.
48787294600003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16257024, while the sum is 58.
The spelling of 48787294600003 in words is "forty-eight trillion, seven hundred eighty-seven billion, two hundred ninety-four million, six hundred thousand, three".
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