Base | Representation |
---|---|
bin | 10110001110100110011111… |
… | …10110111100000001001011 |
3 | 20102001220101020100010211021 |
4 | 23013103033312330001023 |
5 | 22401323140032120203 |
6 | 251543132201013311 |
7 | 13203323204062453 |
oct | 1307231766740113 |
9 | 212056336303737 |
10 | 48880215113803 |
11 | 14635a8a144287 |
12 | 5595391184237 |
13 | 21374cc9b9768 |
14 | c0db5a652d63 |
15 | 59b7472855bd |
hex | 2c74cfdbc04b |
48880215113803 has 2 divisors, whose sum is σ = 48880215113804. Its totient is φ = 48880215113802.
The previous prime is 48880215113677. The next prime is 48880215113857. The reversal of 48880215113803 is 30831151208884.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 48880215113803 - 221 = 48880213016651 is a prime.
It is a super-2 number, since 2×488802151138032 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (48880215113603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24440107556901 + 24440107556902.
It is an arithmetic number, because the mean of its divisors is an integer number (24440107556902).
Almost surely, 248880215113803 is an apocalyptic number.
48880215113803 is a deficient number, since it is larger than the sum of its proper divisors (1).
48880215113803 is an equidigital number, since it uses as much as digits as its factorization.
48880215113803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1474560, while the sum is 52.
The spelling of 48880215113803 in words is "forty-eight trillion, eight hundred eighty billion, two hundred fifteen million, one hundred thirteen thousand, eight hundred three".
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