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489135403 is a prime number
BaseRepresentation
bin11101001001111…
…001110100101011
31021002101122122001
4131021321310223
52000204313103
6120311511431
715056403511
oct3511716453
91232348561
10489135403
11231116739
12117988577
137a44cb43
1448d684b1
152ce1e01d
hex1d279d2b

489135403 has 2 divisors, whose sum is σ = 489135404. Its totient is φ = 489135402.

The previous prime is 489135397. The next prime is 489135421. The reversal of 489135403 is 304531984.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 489135403 - 213 = 489127211 is a prime.

It is not a weakly prime, because it can be changed into another prime (489135103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 244567701 + 244567702.

It is an arithmetic number, because the mean of its divisors is an integer number (244567702).

Almost surely, 2489135403 is an apocalyptic number.

489135403 is a deficient number, since it is larger than the sum of its proper divisors (1).

489135403 is an equidigital number, since it uses as much as digits as its factorization.

489135403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 37.

The square root of 489135403 is about 22116.4057432486. The cubic root of 489135403 is about 787.9095525852.

The spelling of 489135403 in words is "four hundred eighty-nine million, one hundred thirty-five thousand, four hundred three".