48972495611203 has 2 divisors, whose sum is σ = 48972495611204. Its totient is φ = 48972495611202.

The previous prime is 48972495611159. The next prime is 48972495611267. The reversal of 48972495611203 is 30211659427984.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 48972495611203 - 2¹³ = 48972495603011 is a prime.

It is not a weakly prime, because it can be changed into another prime (48972495615203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24486247805601 + 24486247805602.

It is an arithmetic number, because the mean of its divisors is an integer number (24486247805602).

It is a 1-persistent number, because it is pandigital, but 2⋅48972495611203 = 97944991222406 is not.

Almost surely, 2^{48972495611203} is an apocalyptic number.

48972495611203 is a deficient number, since it is larger than the sum of its proper divisors (1).

48972495611203 is an equidigital number, since it uses as much as digits as its factorization.

48972495611203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26127360, while the sum is 61.

The spelling of 48972495611203 in words is "forty-eight trillion, nine hundred seventy-two billion, four hundred ninety-five million, six hundred eleven thousand, two hundred three".