Base | Representation |
---|---|
bin | 101101100111001101… |
… | …100110001111110001 |
3 | 11200102020110200122201 |
4 | 231213031212033301 |
5 | 1300300410224113 |
6 | 34255511103201 |
7 | 3352451216203 |
oct | 554715461761 |
9 | 150366420581 |
10 | 48976258033 |
11 | 1985290360a |
12 | 95aa071b01 |
13 | 480693c151 |
14 | 25287a2773 |
15 | 1419a73cdd |
hex | b673663f1 |
48976258033 has 2 divisors, whose sum is σ = 48976258034. Its totient is φ = 48976258032.
The previous prime is 48976257971. The next prime is 48976258049. The reversal of 48976258033 is 33085267984.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29905476624 + 19070781409 = 172932^2 + 138097^2 .
It is a cyclic number.
It is not a de Polignac number, because 48976258033 - 233 = 40386323441 is a prime.
It is not a weakly prime, because it can be changed into another prime (48976258063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24488129016 + 24488129017.
It is an arithmetic number, because the mean of its divisors is an integer number (24488129017).
Almost surely, 248976258033 is an apocalyptic number.
It is an amenable number.
48976258033 is a deficient number, since it is larger than the sum of its proper divisors (1).
48976258033 is an equidigital number, since it uses as much as digits as its factorization.
48976258033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8709120, while the sum is 55.
The spelling of 48976258033 in words is "forty-eight billion, nine hundred seventy-six million, two hundred fifty-eight thousand, thirty-three".
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