Base | Representation |
---|---|
bin | 100011101010010000011… |
… | …1011010101101101110011 |
3 | 122100112121210100021022002 |
4 | 1013110200323111231303 |
5 | 1120244433142023331 |
6 | 14231312223004215 |
7 | 1014044035401125 |
oct | 107244073255563 |
9 | 18315553307262 |
10 | 4901110111091 |
11 | 161a604982347 |
12 | 671a4ba3966b |
13 | 2972325657bc |
14 | 12d301d37215 |
15 | 87750bb89cb |
hex | 47520ed5b73 |
4901110111091 has 2 divisors, whose sum is σ = 4901110111092. Its totient is φ = 4901110111090.
The previous prime is 4901110111063. The next prime is 4901110111097. The reversal of 4901110111091 is 1901110111094.
4901110111091 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4901110111091 - 210 = 4901110110067 is a prime.
It is a super-2 number, since 2×49011101110912 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4901110111097) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2450555055545 + 2450555055546.
It is an arithmetic number, because the mean of its divisors is an integer number (2450555055546).
Almost surely, 24901110111091 is an apocalyptic number.
4901110111091 is a deficient number, since it is larger than the sum of its proper divisors (1).
4901110111091 is an equidigital number, since it uses as much as digits as its factorization.
4901110111091 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 29.
The spelling of 4901110111091 in words is "four trillion, nine hundred one billion, one hundred ten million, one hundred eleven thousand, ninety-one".
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