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49013762933521 is a prime number
BaseRepresentation
bin10110010010011111001111…
…11011011100001100010001
320102112200002102010022011101
423021033213323130030101
522411020141302333041
6252124340054144401
713216061510603521
oct1311174773341421
9212480072108141
1049013762933521
1114687690431921
1255b7242052101
132146c939017a9
14c163c8da7681
1559ee617eeb31
hex2c93e7edc311

49013762933521 has 2 divisors, whose sum is σ = 49013762933522. Its totient is φ = 49013762933520.

The previous prime is 49013762933453. The next prime is 49013762933539. The reversal of 49013762933521 is 12533926731094.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29247167044225 + 19766595889296 = 5408065^2 + 4445964^2 .

It is a cyclic number.

It is not a de Polignac number, because 49013762933521 - 213 = 49013762925329 is a prime.

It is a super-3 number, since 3×490137629335213 (a number of 42 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (49013762933321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24506881466760 + 24506881466761.

It is an arithmetic number, because the mean of its divisors is an integer number (24506881466761).

Almost surely, 249013762933521 is an apocalyptic number.

It is an amenable number.

49013762933521 is a deficient number, since it is larger than the sum of its proper divisors (1).

49013762933521 is an equidigital number, since it uses as much as digits as its factorization.

49013762933521 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7348320, while the sum is 55.

The spelling of 49013762933521 in words is "forty-nine trillion, thirteen billion, seven hundred sixty-two million, nine hundred thirty-three thousand, five hundred twenty-one".