Base | Representation |
---|---|
bin | 10110010010101101101001… |
… | …10000101100000100110001 |
3 | 20102120102001020021002012012 |
4 | 23021112310300230010301 |
5 | 22411132010032132234 |
6 | 252132055202412305 |
7 | 13216454221230041 |
oct | 1311266460540461 |
9 | 212512036232165 |
10 | 49021494411569 |
11 | 1468a9986757a9 |
12 | 55b883b361095 |
13 | 2147926618784 |
14 | c1691db33721 |
15 | 5a02654580ce |
hex | 2c95b4c2c131 |
49021494411569 has 2 divisors, whose sum is σ = 49021494411570. Its totient is φ = 49021494411568.
The previous prime is 49021494411553. The next prime is 49021494411577. The reversal of 49021494411569 is 96511449412094.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30300841344400 + 18720653067169 = 5504620^2 + 4326737^2 .
It is a cyclic number.
It is not a de Polignac number, because 49021494411569 - 24 = 49021494411553 is a prime.
It is a super-3 number, since 3×490214944115693 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (49021494414569) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24510747205784 + 24510747205785.
It is an arithmetic number, because the mean of its divisors is an integer number (24510747205785).
Almost surely, 249021494411569 is an apocalyptic number.
It is an amenable number.
49021494411569 is a deficient number, since it is larger than the sum of its proper divisors (1).
49021494411569 is an equidigital number, since it uses as much as digits as its factorization.
49021494411569 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11197440, while the sum is 59.
The spelling of 49021494411569 in words is "forty-nine trillion, twenty-one billion, four hundred ninety-four million, four hundred eleven thousand, five hundred sixty-nine".
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