Base | Representation |
---|---|
bin | 100011101010101111101… |
… | …0100100110011001000011 |
3 | 122100122022202002200200202 |
4 | 1013111133110212121003 |
5 | 1120304104132423022 |
6 | 14232004135435415 |
7 | 1014112006210226 |
oct | 107253724463103 |
9 | 18318282080622 |
10 | 4902156920387 |
11 | 161aaa18676a1 |
12 | 6720a2525b6b |
13 | 29736b3b199c |
14 | 12d3a0d8b5bd |
15 | 877b2a44592 |
hex | 4755f526643 |
4902156920387 has 2 divisors, whose sum is σ = 4902156920388. Its totient is φ = 4902156920386.
The previous prime is 4902156920359. The next prime is 4902156920473. The reversal of 4902156920387 is 7830296512094.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4902156920387 - 214 = 4902156904003 is a prime.
It is a super-2 number, since 2×49021569203872 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4902156920587) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2451078460193 + 2451078460194.
It is an arithmetic number, because the mean of its divisors is an integer number (2451078460194).
It is a 1-persistent number, because it is pandigital, but 2⋅4902156920387 = 9804313840774 is not.
Almost surely, 24902156920387 is an apocalyptic number.
4902156920387 is a deficient number, since it is larger than the sum of its proper divisors (1).
4902156920387 is an equidigital number, since it uses as much as digits as its factorization.
4902156920387 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6531840, while the sum is 56.
The spelling of 4902156920387 in words is "four trillion, nine hundred two billion, one hundred fifty-six million, nine hundred twenty thousand, three hundred eighty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 5.074 sec. • engine limits •