Base | Representation |
---|---|
bin | 1001001000011111… |
… | …01011010010110011 |
3 | 110122200222002011112 |
4 | 10210033223102303 |
5 | 40020140302223 |
6 | 2130305303535 |
7 | 232334202356 |
oct | 44417532263 |
9 | 13580862145 |
10 | 4903056563 |
11 | 2096713a69 |
12 | b4a034bab |
13 | 601a48402 |
14 | 34726829d |
15 | 1da6a7778 |
hex | 1243eb4b3 |
4903056563 has 2 divisors, whose sum is σ = 4903056564. Its totient is φ = 4903056562.
The previous prime is 4903056551. The next prime is 4903056569. The reversal of 4903056563 is 3656503094.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4903056563 - 222 = 4898862259 is a prime.
It is an alternating number because its digits alternate between even and odd.
It is a self number, because there is not a number n which added to its sum of digits gives 4903056563.
It is not a weakly prime, because it can be changed into another prime (4903056569) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2451528281 + 2451528282.
It is an arithmetic number, because the mean of its divisors is an integer number (2451528282).
Almost surely, 24903056563 is an apocalyptic number.
4903056563 is a deficient number, since it is larger than the sum of its proper divisors (1).
4903056563 is an equidigital number, since it uses as much as digits as its factorization.
4903056563 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 291600, while the sum is 41.
The square root of 4903056563 is about 70021.8291891893. The cubic root of 4903056563 is about 1698.8523468584.
The spelling of 4903056563 in words is "four billion, nine hundred three million, fifty-six thousand, five hundred sixty-three".
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