49041295119 has 24 divisors (see below), whose sum is σ = 71083995840. Its totient is φ = 32580539712.

The previous prime is 49041295111. The next prime is 49041295123. The reversal of 49041295119 is 91159214094.

49041295119 is a `hidden beast` number, since 4 + 9 + 0 + 4 + 129 + 511 + 9 = 666.

It is not a de Polignac number, because 49041295119 - 2³ = 49041295111 is a prime.

It is a super-3 number, since 3×49041295119³ (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (49041295111) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4792042 + ... + 4802264.

It is an arithmetic number, because the mean of its divisors is an integer number (2961833160).

Almost surely, 2^49041295119 is an apocalyptic number.

49041295119 is a deficient number, since it is larger than the sum of its proper divisors (22042700721).

49041295119 is a wasteful number, since it uses less digits than its factorization.

49041295119 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12031 (or 12028 counting only the distinct ones).

The product of its (nonzero) digits is 116640, while the sum is 45.

The spelling of 49041295119 in words is "forty-nine billion, forty-one million, two hundred ninety-five thousand, one hundred nineteen".