Search a number
-
+
490675796113 is a prime number
BaseRepresentation
bin1110010001111101000…
…11100111100010010001
31201220112001002002002211
413020332203213202101
531014401000433423
61013225141112121
750310255310426
oct7107643474221
91656461062084
10490675796113
1117a104771078
127b11a3b8641
1337369476c79
1419a6ab37d4d
15cb6c26610d
hex723e8e7891

490675796113 has 2 divisors, whose sum is σ = 490675796114. Its totient is φ = 490675796112.

The previous prime is 490675796101. The next prime is 490675796123. The reversal of 490675796113 is 311697576094.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 310312501249 + 180363294864 = 557057^2 + 424692^2 .

It is a cyclic number.

It is not a de Polignac number, because 490675796113 - 221 = 490673698961 is a prime.

It is a super-2 number, since 2×4906757961132 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (490675796123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245337898056 + 245337898057.

It is an arithmetic number, because the mean of its divisors is an integer number (245337898057).

Almost surely, 2490675796113 is an apocalyptic number.

It is an amenable number.

490675796113 is a deficient number, since it is larger than the sum of its proper divisors (1).

490675796113 is an equidigital number, since it uses as much as digits as its factorization.

490675796113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8573040, while the sum is 58.

The spelling of 490675796113 in words is "four hundred ninety billion, six hundred seventy-five million, seven hundred ninety-six thousand, one hundred thirteen".