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490715997281 is a prime number
BaseRepresentation
bin1110010010000001111…
…00111110010001100001
31201220121211201111201222
413021000330332101201
531014441243403111
61013233134504425
750311254104126
oct7110074762141
91656554644658
10490715997281
1117a125429884
127b12b965115
13373748b1243
1419a7220074d
15cb70a577db
hex7240f3e461

490715997281 has 2 divisors, whose sum is σ = 490715997282. Its totient is φ = 490715997280.

The previous prime is 490715997223. The next prime is 490715997313. The reversal of 490715997281 is 182799517094.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 354197571025 + 136518426256 = 595145^2 + 369484^2 .

It is a cyclic number.

It is not a de Polignac number, because 490715997281 - 26 = 490715997217 is a prime.

It is a super-2 number, since 2×4907159972812 (a number of 24 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (490715997581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245357998640 + 245357998641.

It is an arithmetic number, because the mean of its divisors is an integer number (245357998641).

Almost surely, 2490715997281 is an apocalyptic number.

It is an amenable number.

490715997281 is a deficient number, since it is larger than the sum of its proper divisors (1).

490715997281 is an equidigital number, since it uses as much as digits as its factorization.

490715997281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11430720, while the sum is 62.

The spelling of 490715997281 in words is "four hundred ninety billion, seven hundred fifteen million, nine hundred ninety-seven thousand, two hundred eighty-one".