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490715997433 is a prime number
BaseRepresentation
bin1110010010000001111…
…00111110010011111001
31201220121211201111221121
413021000330332103321
531014441243404213
61013233134505241
750311254104434
oct7110074762371
91656554644847
10490715997433
1117a125429a02
127b12b965221
13373748b132c
1419a7220081b
15cb70a5788d
hex7240f3e4f9

490715997433 has 2 divisors, whose sum is σ = 490715997434. Its totient is φ = 490715997432.

The previous prime is 490715997397. The next prime is 490715997437. The reversal of 490715997433 is 334799517094.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 441703793664 + 49012203769 = 664608^2 + 221387^2 .

It is a cyclic number.

It is not a de Polignac number, because 490715997433 - 213 = 490715989241 is a prime.

It is not a weakly prime, because it can be changed into another prime (490715997437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245357998716 + 245357998717.

It is an arithmetic number, because the mean of its divisors is an integer number (245357998717).

Almost surely, 2490715997433 is an apocalyptic number.

It is an amenable number.

490715997433 is a deficient number, since it is larger than the sum of its proper divisors (1).

490715997433 is an equidigital number, since it uses as much as digits as its factorization.

490715997433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25719120, while the sum is 61.

The spelling of 490715997433 in words is "four hundred ninety billion, seven hundred fifteen million, nine hundred ninety-seven thousand, four hundred thirty-three".