Base | Representation |
---|---|
bin | 100011101101111010100… |
… | …0000001111001010001001 |
3 | 122101021220002012001211212 |
4 | 1013123311000033022021 |
5 | 1120412024030211131 |
6 | 14235051352302505 |
7 | 1014442453103003 |
oct | 107336500171211 |
9 | 18337802161755 |
10 | 4908963132041 |
11 | 1622974791201 |
12 | 6734819a1a35 |
13 | 297bb44c6a67 |
14 | 12d848ca1373 |
15 | 87a6032ea2b |
hex | 476f500f289 |
4908963132041 has 2 divisors, whose sum is σ = 4908963132042. Its totient is φ = 4908963132040.
The previous prime is 4908963131993. The next prime is 4908963132221. The reversal of 4908963132041 is 1402313698094.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2492912578816 + 2416050553225 = 1578896^2 + 1554365^2 .
It is a cyclic number.
It is not a de Polignac number, because 4908963132041 - 238 = 4634085225097 is a prime.
It is not a weakly prime, because it can be changed into another prime (4908963132641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2454481566020 + 2454481566021.
It is an arithmetic number, because the mean of its divisors is an integer number (2454481566021).
Almost surely, 24908963132041 is an apocalyptic number.
It is an amenable number.
4908963132041 is a deficient number, since it is larger than the sum of its proper divisors (1).
4908963132041 is an equidigital number, since it uses as much as digits as its factorization.
4908963132041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1119744, while the sum is 50.
The spelling of 4908963132041 in words is "four trillion, nine hundred eight billion, nine hundred sixty-three million, one hundred thirty-two thousand, forty-one".
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