Base | Representation |
---|---|
bin | 1110010010011100111… |
… | …01111100011011010001 |
3 | 1201221012122101110010201 |
4 | 13021032131330123101 |
5 | 31020422320304043 |
6 | 1013311434455201 |
7 | 50320006321102 |
oct | 7111635743321 |
9 | 1657178343121 |
10 | 490942744273 |
11 | 17a231420193 |
12 | 7b193894501 |
13 | 373ac871967 |
14 | 19a943863a9 |
15 | cb858e6c4d |
hex | 724e77c6d1 |
490942744273 has 2 divisors, whose sum is σ = 490942744274. Its totient is φ = 490942744272.
The previous prime is 490942744231. The next prime is 490942744339. The reversal of 490942744273 is 372447249094.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 368094597264 + 122848147009 = 606708^2 + 350497^2 .
It is a cyclic number.
It is not a de Polignac number, because 490942744273 - 217 = 490942613201 is a prime.
It is not a weakly prime, because it can be changed into another prime (490942744373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245471372136 + 245471372137.
It is an arithmetic number, because the mean of its divisors is an integer number (245471372137).
Almost surely, 2490942744273 is an apocalyptic number.
It is an amenable number.
490942744273 is a deficient number, since it is larger than the sum of its proper divisors (1).
490942744273 is an equidigital number, since it uses as much as digits as its factorization.
490942744273 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12192768, while the sum is 55.
The spelling of 490942744273 in words is "four hundred ninety billion, nine hundred forty-two million, seven hundred forty-four thousand, two hundred seventy-three".
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