Base | Representation |
---|---|
bin | 101101101111000101… |
… | …110010001011010101 |
3 | 11200202110011121001022 |
4 | 231233011302023111 |
5 | 1301033224134402 |
6 | 34320552010525 |
7 | 3355644513644 |
oct | 555705621325 |
9 | 150673147038 |
10 | 49108427477 |
11 | 1991047745a |
12 | 9626390a45 |
13 | 4828137215 |
14 | 253c16935b |
15 | 14264802a2 |
hex | b6f1722d5 |
49108427477 has 4 divisors (see below), whose sum is σ = 49222368576. Its totient is φ = 48994486380.
The previous prime is 49108427449. The next prime is 49108427491. The reversal of 49108427477 is 77472480194.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 49108427477 - 234 = 31928558293 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (49108427497) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56969903 + ... + 56970764.
It is an arithmetic number, because the mean of its divisors is an integer number (12305592144).
Almost surely, 249108427477 is an apocalyptic number.
It is an amenable number.
49108427477 is a deficient number, since it is larger than the sum of its proper divisors (113941099).
49108427477 is a wasteful number, since it uses less digits than its factorization.
49108427477 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 113941098.
The product of its (nonzero) digits is 3161088, while the sum is 53.
The spelling of 49108427477 in words is "forty-nine billion, one hundred eight million, four hundred twenty-seven thousand, four hundred seventy-seven".
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