Base | Representation |
---|---|
bin | 1011101101010… |
… | …1110011100001 |
3 | 10102102001120211 |
4 | 2323111303201 |
5 | 100033011431 |
6 | 4512334121 |
7 | 1134300355 |
oct | 273256341 |
9 | 112361524 |
10 | 49110241 |
11 | 257a3284 |
12 | 14544341 |
13 | a23641b |
14 | 6745465 |
15 | 44a12b1 |
hex | 2ed5ce1 |
49110241 has 2 divisors, whose sum is σ = 49110242. Its totient is φ = 49110240.
The previous prime is 49110209. The next prime is 49110247. The reversal of 49110241 is 14201194.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 47900241 + 1210000 = 6921^2 + 1100^2 .
It is a cyclic number.
It is not a de Polignac number, because 49110241 - 25 = 49110209 is a prime.
It is not a weakly prime, because it can be changed into another prime (49110247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24555120 + 24555121.
It is an arithmetic number, because the mean of its divisors is an integer number (24555121).
Almost surely, 249110241 is an apocalyptic number.
It is an amenable number.
49110241 is a deficient number, since it is larger than the sum of its proper divisors (1).
49110241 is an equidigital number, since it uses as much as digits as its factorization.
49110241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 22.
The square root of 49110241 is about 7007.8699331537. The cubic root of 49110241 is about 366.2047909811.
The spelling of 49110241 in words is "forty-nine million, one hundred ten thousand, two hundred forty-one".
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