Base | Representation |
---|---|
bin | 100011101110111001000… |
… | …0000001010010001101001 |
3 | 122101111022020022102010102 |
4 | 1013131302000022101221 |
5 | 1120430322411422131 |
6 | 14240035425155145 |
7 | 1014545436323321 |
oct | 107356200122151 |
9 | 18344266272112 |
10 | 4911060264041 |
11 | 1623850540548 |
12 | 67396818bab5 |
13 | 298159b1c379 |
14 | 12d9a7602281 |
15 | 87b344cc1cb |
hex | 4777200a469 |
4911060264041 has 8 divisors (see below), whose sum is σ = 4943737666560. Its totient is φ = 4878477993312.
The previous prime is 4911060264037. The next prime is 4911060264091. The reversal of 4911060264041 is 1404620601194.
It is a happy number.
4911060264041 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4911060264041 - 22 = 4911060264037 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4911060263986 and 4911060264004.
It is not an unprimeable number, because it can be changed into a prime (4911060264031) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23679356 + ... + 23885853.
It is an arithmetic number, because the mean of its divisors is an integer number (617967208320).
Almost surely, 24911060264041 is an apocalyptic number.
It is an amenable number.
4911060264041 is a deficient number, since it is larger than the sum of its proper divisors (32677402519).
4911060264041 is a wasteful number, since it uses less digits than its factorization.
4911060264041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47565895.
The product of its (nonzero) digits is 41472, while the sum is 38.
The spelling of 4911060264041 in words is "four trillion, nine hundred eleven billion, sixty million, two hundred sixty-four thousand, forty-one".
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