Base | Representation |
---|---|
bin | 100011101110111101001… |
… | …0101010010101011001010 |
3 | 122101111122222021210220021 |
4 | 1013131322111102223022 |
5 | 1120431114201134234 |
6 | 14240101340451054 |
7 | 1014552054252505 |
oct | 107357225225312 |
9 | 18344588253807 |
10 | 4911200021194 |
11 | 1623912417125 |
12 | 6739a6b49a8a |
13 | 29817ca72ccc |
14 | 12d9bbdc213c |
15 | 87b418d69b4 |
hex | 4777a552aca |
4911200021194 has 4 divisors (see below), whose sum is σ = 7366800031794. Its totient is φ = 2455600010596.
The previous prime is 4911200021191. The next prime is 4911200021209.
4911200021194 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 4396842828225 + 514357192969 = 2096865^2 + 717187^2 .
It is not an unprimeable number, because it can be changed into a prime (4911200021191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1227800005297 + ... + 1227800005300.
Almost surely, 24911200021194 is an apocalyptic number.
4911200021194 is a deficient number, since it is larger than the sum of its proper divisors (2455600010600).
4911200021194 is a wasteful number, since it uses less digits than its factorization.
4911200021194 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2455600010599.
The product of its (nonzero) digits is 5184, while the sum is 34.
It can be divided in two parts, 49112000 and 21194, that added together give a palindrome (49133194).
The spelling of 4911200021194 in words is "four trillion, nine hundred eleven billion, two hundred million, twenty-one thousand, one hundred ninety-four".
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