Base | Representation |
---|---|
bin | 1110010010110011011… |
… | …11000111010000010111 |
3 | 1201221200211010012020022 |
4 | 13021121233013100113 |
5 | 31021314214410310 |
6 | 1013342310455355 |
7 | 50324463241601 |
oct | 7113157072027 |
9 | 1657624105208 |
10 | 491131794455 |
11 | 17a319104405 |
12 | 7b22706455b |
13 | 3740ca93c83 |
14 | 19ab1518171 |
15 | cb972dba55 |
hex | 7259bc7417 |
491131794455 has 16 divisors (see below), whose sum is σ = 603837297504. Its totient is φ = 383255992320.
The previous prime is 491131794437. The next prime is 491131794457. The reversal of 491131794455 is 554497131194.
It is not a de Polignac number, because 491131794455 - 210 = 491131793431 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 491131794397 and 491131794406.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (491131794457) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 996164 + ... + 1405206.
It is an arithmetic number, because the mean of its divisors is an integer number (37739831094).
Almost surely, 2491131794455 is an apocalyptic number.
491131794455 is a deficient number, since it is larger than the sum of its proper divisors (112705503049).
491131794455 is a wasteful number, since it uses less digits than its factorization.
491131794455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 414946.
The product of its digits is 2721600, while the sum is 53.
The spelling of 491131794455 in words is "four hundred ninety-one billion, one hundred thirty-one million, seven hundred ninety-four thousand, four hundred fifty-five".
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