Base | Representation |
---|---|
bin | 1110010010110111000… |
… | …10000011110011111011 |
3 | 1201221202220211002012001 |
4 | 13021123202003303323 |
5 | 31021344423130112 |
6 | 1013345304401431 |
7 | 50325310331401 |
oct | 7113342036373 |
9 | 1657686732161 |
10 | 491161926907 |
11 | 17a334115363 |
12 | 7b235176277 |
13 | 374160b4322 |
14 | 19ab551d471 |
15 | cb99c8ec57 |
hex | 725b883cfb |
491161926907 has 2 divisors, whose sum is σ = 491161926908. Its totient is φ = 491161926906.
The previous prime is 491161926823. The next prime is 491161926911. The reversal of 491161926907 is 709629161194.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 491161926907 - 27 = 491161926779 is a prime.
It is not a weakly prime, because it can be changed into another prime (491161926967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245580963453 + 245580963454.
It is an arithmetic number, because the mean of its divisors is an integer number (245580963454).
Almost surely, 2491161926907 is an apocalyptic number.
491161926907 is a deficient number, since it is larger than the sum of its proper divisors (1).
491161926907 is an equidigital number, since it uses as much as digits as its factorization.
491161926907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1469664, while the sum is 55.
The spelling of 491161926907 in words is "four hundred ninety-one billion, one hundred sixty-one million, nine hundred twenty-six thousand, nine hundred seven".
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