Base | Representation |
---|---|
bin | 10110010101011111010111… |
… | …01111011010111001010111 |
3 | 20102220112022122012101002110 |
4 | 23022233223233122321113 |
5 | 22414212410430401310 |
6 | 252243554542242103 |
7 | 13226402502241515 |
oct | 1312575357327127 |
9 | 212815278171073 |
10 | 49116906106455 |
11 | 147173aa027300 |
12 | 5613228586333 |
13 | 2153920674075 |
14 | c1b3b165d4b5 |
15 | 5a299b95ed20 |
hex | 2cabebbdae57 |
49116906106455 has 48 divisors (see below), whose sum is σ = 86598391938912. Its totient is φ = 23754271622400.
The previous prime is 49116906106393. The next prime is 49116906106459. The reversal of 49116906106455 is 55460160961194.
It is not a de Polignac number, because 49116906106455 - 27 = 49116906106327 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 49116906106395 and 49116906106404.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (49116906106459) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 33362136 + ... + 34803245.
It is an arithmetic number, because the mean of its divisors is an integer number (1804133165394).
Almost surely, 249116906106455 is an apocalyptic number.
49116906106455 is a deficient number, since it is larger than the sum of its proper divisors (37481485832457).
49116906106455 is a wasteful number, since it uses less digits than its factorization.
49116906106455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68165808 (or 68165797 counting only the distinct ones).
The product of its (nonzero) digits is 6998400, while the sum is 57.
The spelling of 49116906106455 in words is "forty-nine trillion, one hundred sixteen billion, nine hundred six million, one hundred six thousand, four hundred fifty-five".
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