Base | Representation |
---|---|
bin | 1001001001100001… |
… | …11111111100001001 |
3 | 110200022101212202211 |
4 | 10210300333330021 |
5 | 40024404320011 |
6 | 2131220425121 |
7 | 232501353643 |
oct | 44460777411 |
9 | 13608355684 |
10 | 4911791881 |
11 | 20a063aa37 |
12 | b50b481a1 |
13 | 6037b6439 |
14 | 34849d893 |
15 | 1db330b21 |
hex | 124c3ff09 |
4911791881 has 2 divisors, whose sum is σ = 4911791882. Its totient is φ = 4911791880.
The previous prime is 4911791851. The next prime is 4911791891. The reversal of 4911791881 is 1881971194.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4884751881 + 27040000 = 69891^2 + 5200^2 .
It is a cyclic number.
It is not a de Polignac number, because 4911791881 - 25 = 4911791849 is a prime.
It is a super-2 number, since 2×49117918812 = 48251398964515036322, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4911791851) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2455895940 + 2455895941.
It is an arithmetic number, because the mean of its divisors is an integer number (2455895941).
Almost surely, 24911791881 is an apocalyptic number.
It is an amenable number.
4911791881 is a deficient number, since it is larger than the sum of its proper divisors (1).
4911791881 is an equidigital number, since it uses as much as digits as its factorization.
4911791881 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 145152, while the sum is 49.
The square root of 4911791881 is about 70084.1771086741. The cubic root of 4911791881 is about 1699.8606438247.
The spelling of 4911791881 in words is "four billion, nine hundred eleven million, seven hundred ninety-one thousand, eight hundred eighty-one".
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