Search a number
-
+
4912176018643 is a prime number
BaseRepresentation
bin100011101111011010010…
…0000011011010011010011
3122101121011222210121200221
41013132310200123103103
51120440114030044033
614240342243453511
71014615205144225
oct107366440332323
918347158717627
104912176018643
111624273336493
12674019987297
132982a7027caa
1412da71882415
1587b9c42612d
hex477b481b4d3

4912176018643 has 2 divisors, whose sum is σ = 4912176018644. Its totient is φ = 4912176018642.

The previous prime is 4912176018623. The next prime is 4912176018677. The reversal of 4912176018643 is 3468106712194.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4912176018643 - 213 = 4912176010451 is a prime.

It is a super-2 number, since 2×49121760186432 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4912176018623) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2456088009321 + 2456088009322.

It is an arithmetic number, because the mean of its divisors is an integer number (2456088009322).

Almost surely, 24912176018643 is an apocalyptic number.

4912176018643 is a deficient number, since it is larger than the sum of its proper divisors (1).

4912176018643 is an equidigital number, since it uses as much as digits as its factorization.

4912176018643 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1741824, while the sum is 52.

The spelling of 4912176018643 in words is "four trillion, nine hundred twelve billion, one hundred seventy-six million, eighteen thousand, six hundred forty-three".