Base | Representation |
---|---|
bin | 101101110000000001… |
… | …010101000001001011 |
3 | 11200210112112121212001 |
4 | 231300001111001023 |
5 | 1301101223133213 |
6 | 34322310331431 |
7 | 3356224264561 |
oct | 556001250113 |
9 | 150715477761 |
10 | 49124036683 |
11 | 19919268927 |
12 | 962b659b77 |
13 | 482b440c37 |
14 | 254026da31 |
15 | 1427a151dd |
hex | b7005504b |
49124036683 has 2 divisors, whose sum is σ = 49124036684. Its totient is φ = 49124036682.
The previous prime is 49124036641. The next prime is 49124036699. The reversal of 49124036683 is 38663042194.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49124036683 - 213 = 49124028491 is a prime.
It is a super-3 number, since 3×491240366833 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (49124036603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24562018341 + 24562018342.
It is an arithmetic number, because the mean of its divisors is an integer number (24562018342).
Almost surely, 249124036683 is an apocalyptic number.
49124036683 is a deficient number, since it is larger than the sum of its proper divisors (1).
49124036683 is an equidigital number, since it uses as much as digits as its factorization.
49124036683 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 746496, while the sum is 46.
The spelling of 49124036683 in words is "forty-nine billion, one hundred twenty-four million, thirty-six thousand, six hundred eighty-three".
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