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49125107 is a prime number
BaseRepresentation
bin1011101101100…
…1011011110011
310102102210222102
42323121123303
5100034000412
64512531015
71134361613
oct273313363
9112383872
1049125107
1125803469
1214550a6b
13a240115
14674aa43
1544a58c2
hex2ed96f3

49125107 has 2 divisors, whose sum is σ = 49125108. Its totient is φ = 49125106.

The previous prime is 49125077. The next prime is 49125133. The reversal of 49125107 is 70152194.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-49125107 is a prime.

It is a super-2 number, since 2×491251072 = 4826552275522898, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 49125107.

It is not a weakly prime, because it can be changed into another prime (49125157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24562553 + 24562554.

It is an arithmetic number, because the mean of its divisors is an integer number (24562554).

Almost surely, 249125107 is an apocalyptic number.

49125107 is a deficient number, since it is larger than the sum of its proper divisors (1).

49125107 is an equidigital number, since it uses as much as digits as its factorization.

49125107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2520, while the sum is 29.

The square root of 49125107 is about 7008.9305175611. The cubic root of 49125107 is about 366.2417381371.

The spelling of 49125107 in words is "forty-nine million, one hundred twenty-five thousand, one hundred seven".