491277938353 has 4 divisors (see below), whose sum is σ = 491305342320. Its totient is φ = 491250534388.

The previous prime is 491277938287. The next prime is 491277938357. The reversal of 491277938353 is 353839772194.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 353839772194 = 2 ⋅176919886097.

It is a cyclic number.

It is not a de Polignac number, because 491277938353 - 2⁹ = 491277937841 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 491277938291 and 491277938300.

It is not an unprimeable number, because it can be changed into a prime (491277938357) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13675075 + ... + 13710952.

It is an arithmetic number, because the mean of its divisors is an integer number (122826335580).

Almost surely, 2^491277938353 is an apocalyptic number.

It is an amenable number.

491277938353 is a deficient number, since it is larger than the sum of its proper divisors (27403967).

491277938353 is a wasteful number, since it uses less digits than its factorization.

491277938353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27403966.

The product of its digits is 34292160, while the sum is 61.

The spelling of 491277938353 in words is "four hundred ninety-one billion, two hundred seventy-seven million, nine hundred thirty-eight thousand, three hundred fifty-three".