Base | Representation |
---|---|
bin | 100011101111110101110… |
… | …0011001011010101010110 |
3 | 122101200120100110122112000 |
4 | 1013133223203023111112 |
5 | 1120444011432032200 |
6 | 14241014032540130 |
7 | 1014650120404413 |
oct | 107375343132526 |
9 | 18350510418460 |
10 | 4913099486550 |
11 | 16246a7637602 |
12 | 6742370b1646 |
13 | 2983c344a3c8 |
14 | 12db1c38b10a |
15 | 87c0353b300 |
hex | 477eb8cb556 |
4913099486550 has 192 divisors, whose sum is σ = 14345897428800. Its totient is φ = 1232127590400.
The previous prime is 4913099486509. The next prime is 4913099486569. The reversal of 4913099486550 is 556849903194.
4913099486550 is a `hidden beast` number, since 4 + 9 + 1 + 30 + 9 + 9 + 48 + 6 + 550 = 666.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 29499510 + ... + 29665590.
It is an arithmetic number, because the mean of its divisors is an integer number (74718215775).
Almost surely, 24913099486550 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 4913099486550, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (7172948714400).
4913099486550 is an abundant number, since it is smaller than the sum of its proper divisors (9432797942250).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4913099486550 is a wasteful number, since it uses less digits than its factorization.
4913099486550 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 167408 (or 167397 counting only the distinct ones).
The product of its (nonzero) digits is 41990400, while the sum is 63.
The spelling of 4913099486550 in words is "four trillion, nine hundred thirteen billion, ninety-nine million, four hundred eighty-six thousand, five hundred fifty".
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