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491317811712 = 29327133731667
BaseRepresentation
bin1110010011001001101…
…00101101101000000000
31201222011210010211221100
413021210310231220000
531022204324433322
61013412553454400
750332212331140
oct7114464555000
91658153124840
10491317811712
1117a404106982
127b279411400
133743c493960
1419acc0da920
15cba87d2dac
hex7264d2da00

491317811712 has 480 divisors, whose sum is σ = 1792426027392. Its totient is φ = 126072225792.

The previous prime is 491317811707. The next prime is 491317811713. The reversal of 491317811712 is 217118713194.

491317811712 is a `hidden beast` number, since 4 + 91 + 317 + 81 + 171 + 2 = 666.

It is a nude number because it is divisible by every one of its digits.

It is not an unprimeable number, because it can be changed into a prime (491317811713) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 15499303 + ... + 15530969.

Almost surely, 2491317811712 is an apocalyptic number.

491317811712 is a gapful number since it is divisible by the number (42) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 491317811712, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (896213013696).

491317811712 is an abundant number, since it is smaller than the sum of its proper divisors (1301108215680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

491317811712 is a wasteful number, since it uses less digits than its factorization.

491317811712 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31748 (or 31729 counting only the distinct ones).

The product of its digits is 84672, while the sum is 45.

The spelling of 491317811712 in words is "four hundred ninety-one billion, three hundred seventeen million, eight hundred eleven thousand, seven hundred twelve".