Base | Representation |
---|---|
bin | 1110010011001100100… |
… | …11001001111010111011 |
3 | 1201222020111201122202101 |
4 | 13021212103021322323 |
5 | 31022232144203042 |
6 | 1013415240244231 |
7 | 50332632633223 |
oct | 7114623117273 |
9 | 1658214648671 |
10 | 491342569147 |
11 | 17a417086571 |
12 | 7b285770677 |
13 | 37444651621 |
14 | 19ad1503083 |
15 | cbaaa736b7 |
hex | 72664c9ebb |
491342569147 has 2 divisors, whose sum is σ = 491342569148. Its totient is φ = 491342569146.
The previous prime is 491342569051. The next prime is 491342569163. The reversal of 491342569147 is 741965243194.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-491342569147 is a prime.
It is not a weakly prime, because it can be changed into another prime (491342069147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245671284573 + 245671284574.
It is an arithmetic number, because the mean of its divisors is an integer number (245671284574).
Almost surely, 2491342569147 is an apocalyptic number.
491342569147 is a deficient number, since it is larger than the sum of its proper divisors (1).
491342569147 is an equidigital number, since it uses as much as digits as its factorization.
491342569147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6531840, while the sum is 55.
The spelling of 491342569147 in words is "four hundred ninety-one billion, three hundred forty-two million, five hundred sixty-nine thousand, one hundred forty-seven".
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