Base | Representation |
---|---|
bin | 10110010110000011100101… |
… | …11000101111110110100001 |
3 | 20102222101111221121110002002 |
4 | 23023001302320233312201 |
5 | 22420022222424014204 |
6 | 252300532404133345 |
7 | 13230661433113004 |
oct | 1313016270576641 |
9 | 212871457543062 |
10 | 49136353344929 |
11 | 14724679532414 |
12 | 5616b55397255 |
13 | 21556cc682576 |
14 | c1c2d837753b |
15 | 5a3238dde91e |
hex | 2cb072e2fda1 |
49136353344929 has 2 divisors, whose sum is σ = 49136353344930. Its totient is φ = 49136353344928.
The previous prime is 49136353344917. The next prime is 49136353344937. The reversal of 49136353344929 is 92944335363194.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 37831110490000 + 11305242854929 = 6150700^2 + 3362327^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-49136353344929 is a prime.
It is not a weakly prime, because it can be changed into another prime (49136353343929) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24568176672464 + 24568176672465.
It is an arithmetic number, because the mean of its divisors is an integer number (24568176672465).
Almost surely, 249136353344929 is an apocalyptic number.
It is an amenable number.
49136353344929 is a deficient number, since it is larger than the sum of its proper divisors (1).
49136353344929 is an equidigital number, since it uses as much as digits as its factorization.
49136353344929 is an evil number, because the sum of its binary digits is even.
The product of its digits is 226748160, while the sum is 65.
The spelling of 49136353344929 in words is "forty-nine trillion, one hundred thirty-six billion, three hundred fifty-three million, three hundred forty-four thousand, nine hundred twenty-nine".
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