Base | Representation |
---|---|
bin | 10110010110000011100101… |
… | …11000101111110110100111 |
3 | 20102222101111221121110002022 |
4 | 23023001302320233312213 |
5 | 22420022222424014220 |
6 | 252300532404133355 |
7 | 13230661433113013 |
oct | 1313016270576647 |
9 | 212871457543068 |
10 | 49136353344935 |
11 | 1472467953241a |
12 | 5616b5539725b |
13 | 21556cc68257c |
14 | c1c2d8377543 |
15 | 5a3238dde925 |
hex | 2cb072e2fda7 |
49136353344935 has 8 divisors (see below), whose sum is σ = 59709999001920. Its totient is φ = 38811499350624.
The previous prime is 49136353344929. The next prime is 49136353344937. The reversal of 49136353344935 is 53944335363194.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 49136353344935 - 216 = 49136353279399 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (49136353344937) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 62197915232 + ... + 62197916021.
It is an arithmetic number, because the mean of its divisors is an integer number (7463749875240).
Almost surely, 249136353344935 is an apocalyptic number.
49136353344935 is a deficient number, since it is larger than the sum of its proper divisors (10573645656985).
49136353344935 is a wasteful number, since it uses less digits than its factorization.
49136353344935 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 124395831337.
The product of its digits is 188956800, while the sum is 62.
The spelling of 49136353344935 in words is "forty-nine trillion, one hundred thirty-six billion, three hundred fifty-three million, three hundred forty-four thousand, nine hundred thirty-five".
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