Base | Representation |
---|---|
bin | 1110010011010111000… |
… | …01011011111011011011 |
3 | 1201222110121121201022121 |
4 | 13021223201123323123 |
5 | 31022422112332003 |
6 | 1013432050402111 |
7 | 50335045524652 |
oct | 7115341337333 |
9 | 1658417551277 |
10 | 491430199003 |
11 | 17a461599137 |
12 | 7b2aab90337 |
13 | 37459853803 |
14 | 19adcdd4199 |
15 | cbb35d2cbd |
hex | 726b85bedb |
491430199003 has 2 divisors, whose sum is σ = 491430199004. Its totient is φ = 491430199002.
The previous prime is 491430198977. The next prime is 491430199019. The reversal of 491430199003 is 300991034194.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 491430199003 - 233 = 482840264411 is a prime.
It is not a weakly prime, because it can be changed into another prime (491430199033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245715099501 + 245715099502.
It is an arithmetic number, because the mean of its divisors is an integer number (245715099502).
Almost surely, 2491430199003 is an apocalyptic number.
491430199003 is a deficient number, since it is larger than the sum of its proper divisors (1).
491430199003 is an equidigital number, since it uses as much as digits as its factorization.
491430199003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 104976, while the sum is 43.
The spelling of 491430199003 in words is "four hundred ninety-one billion, four hundred thirty million, one hundred ninety-nine thousand, three".
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