4914441001 has 2 divisors, whose sum is σ = 4914441002. Its totient is φ = 4914441000.

The previous prime is 4914440983. The next prime is 4914441011. The reversal of 4914441001 is 1001444194.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4777574400 + 136866601 = 69120^2 + 11699^2 .

It is a cyclic number.

It is not a de Polignac number, because 4914441001 - 2⁵ = 4914440969 is a prime.

It is not a weakly prime, because it can be changed into another prime (4914441011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2457220500 + 2457220501.

It is an arithmetic number, because the mean of its divisors is an integer number (2457220501).

Almost surely, 2^4914441001 is an apocalyptic number.

It is an amenable number.

4914441001 is a deficient number, since it is larger than the sum of its proper divisors (1).

4914441001 is an equidigital number, since it uses as much as digits as its factorization.

4914441001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 28.

The square root of 4914441001 is about 70103.0741194707. The cubic root of 4914441001 is about 1700.1661891741.

Adding to 4914441001 its reverse (1001444194), we get a palindrome (5915885195).

The spelling of 4914441001 in words is "four billion, nine hundred fourteen million, four hundred forty-one thousand, one".