4914742903 has 4 divisors (see below), whose sum is σ = 5616849040. Its totient is φ = 4212636768.

The previous prime is 4914742873. The next prime is 4914742907. The reversal of 4914742903 is 3092474194.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3092474194 = 2 ⋅1546237097.

It is a cyclic number.

It is not a de Polignac number, because 4914742903 - 2⁵ = 4914742871 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4914742903.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4914742907) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 351053058 + ... + 351053071.

It is an arithmetic number, because the mean of its divisors is an integer number (1404212260).

Almost surely, 2^4914742903 is an apocalyptic number.

4914742903 is a deficient number, since it is larger than the sum of its proper divisors (702106137).

4914742903 is an equidigital number, since it uses as much as digits as its factorization.

4914742903 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 702106136.

The product of its (nonzero) digits is 217728, while the sum is 43.

The square root of 4914742903 is about 70105.2273585929. The cubic root of 4914742903 is about 1700.2010031073.

The spelling of 4914742903 in words is "four billion, nine hundred fourteen million, seven hundred forty-two thousand, nine hundred three".