Base | Representation |
---|---|
bin | 101101110100000110… |
… | …100000001101110111 |
3 | 11200222022101000210112 |
4 | 231310012200031313 |
5 | 1301221240032020 |
6 | 34333154013235 |
7 | 3361015240400 |
oct | 556406401567 |
9 | 150868330715 |
10 | 49192502135 |
11 | 19953980a47 |
12 | 964a57721b |
13 | 483c69313a |
14 | 25493b29a7 |
15 | 142da3b2c5 |
hex | b741a0377 |
49192502135 has 24 divisors (see below), whose sum is σ = 68679838080. Its totient is φ = 33726538944.
The previous prime is 49192502119. The next prime is 49192502147. The reversal of 49192502135 is 53120529194.
49192502135 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 49192502135 - 24 = 49192502119 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 49192502092 and 49192502101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2018201 + ... + 2042429.
It is an arithmetic number, because the mean of its divisors is an integer number (2861659920).
Almost surely, 249192502135 is an apocalyptic number.
49192502135 is a deficient number, since it is larger than the sum of its proper divisors (19487335945).
49192502135 is a wasteful number, since it uses less digits than its factorization.
49192502135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32535 (or 32528 counting only the distinct ones).
The product of its (nonzero) digits is 97200, while the sum is 41.
The spelling of 49192502135 in words is "forty-nine billion, one hundred ninety-two million, five hundred two thousand, one hundred thirty-five".
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