Base | Representation |
---|---|
bin | 101101110101000111… |
… | …011010111001100001 |
3 | 11201000111101121112012 |
4 | 231311013122321201 |
5 | 1301240114112323 |
6 | 34335002442305 |
7 | 3361313005334 |
oct | 556507327141 |
9 | 151014347465 |
10 | 49209519713 |
11 | 19962544562 |
12 | 9654203395 |
13 | 4843070c03 |
14 | 254b76261b |
15 | 143029d678 |
hex | b751dae61 |
49209519713 has 2 divisors, whose sum is σ = 49209519714. Its totient is φ = 49209519712.
The previous prime is 49209519649. The next prime is 49209519719. The reversal of 49209519713 is 31791590294.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 47848500049 + 1361019664 = 218743^2 + 36892^2 .
It is a cyclic number.
It is not a de Polignac number, because 49209519713 - 26 = 49209519649 is a prime.
It is not a weakly prime, because it can be changed into another prime (49209519719) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24604759856 + 24604759857.
It is an arithmetic number, because the mean of its divisors is an integer number (24604759857).
Almost surely, 249209519713 is an apocalyptic number.
It is an amenable number.
49209519713 is a deficient number, since it is larger than the sum of its proper divisors (1).
49209519713 is an equidigital number, since it uses as much as digits as its factorization.
49209519713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 612360, while the sum is 50.
The spelling of 49209519713 in words is "forty-nine billion, two hundred nine million, five hundred nineteen thousand, seven hundred thirteen".
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