Base | Representation |
---|---|
bin | 1001001010101111… |
… | …10010110111111111 |
3 | 110201000112120112021 |
4 | 10211113302313333 |
5 | 40040010240413 |
6 | 2132222421011 |
7 | 232653662251 |
oct | 44527626777 |
9 | 13630476467 |
10 | 4921961983 |
11 | 20a6356984 |
12 | b54431767 |
13 | 605937553 |
14 | 349989cd1 |
15 | 1dc18e18d |
hex | 1255f2dff |
4921961983 has 4 divisors (see below), whose sum is σ = 5091684840. Its totient is φ = 4752239128.
The previous prime is 4921961939. The next prime is 4921961987. The reversal of 4921961983 is 3891691294.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3891691294 = 2 ⋅1945845647.
It is a cyclic number.
It is not a de Polignac number, because 4921961983 - 217 = 4921830911 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 4921961983.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4921961987) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84861385 + ... + 84861442.
It is an arithmetic number, because the mean of its divisors is an integer number (1272921210).
Almost surely, 24921961983 is an apocalyptic number.
4921961983 is a deficient number, since it is larger than the sum of its proper divisors (169722857).
4921961983 is a wasteful number, since it uses less digits than its factorization.
4921961983 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 169722856.
The product of its digits is 839808, while the sum is 52.
The square root of 4921961983 is about 70156.6959241953. The cubic root of 4921961983 is about 1701.0330495066.
The spelling of 4921961983 in words is "four billion, nine hundred twenty-one million, nine hundred sixty-one thousand, nine hundred eighty-three".
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