Base | Representation |
---|---|
bin | 101101110111010001… |
… | …000001011101001011 |
3 | 11201010000021020112112 |
4 | 231313101001131023 |
5 | 1301323332410441 |
6 | 34342331532535 |
7 | 3362231422454 |
oct | 556721013513 |
9 | 151100236475 |
10 | 49245591371 |
11 | 19980941749 |
12 | 96642ba14b |
13 | 484a6906a2 |
14 | 255247212b |
15 | 14335264eb |
hex | b7744174b |
49245591371 has 2 divisors, whose sum is σ = 49245591372. Its totient is φ = 49245591370.
The previous prime is 49245591349. The next prime is 49245591379. The reversal of 49245591371 is 17319554294.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-49245591371 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (49245591379) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24622795685 + 24622795686.
It is an arithmetic number, because the mean of its divisors is an integer number (24622795686).
Almost surely, 249245591371 is an apocalyptic number.
49245591371 is a deficient number, since it is larger than the sum of its proper divisors (1).
49245591371 is an equidigital number, since it uses as much as digits as its factorization.
49245591371 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1360800, while the sum is 50.
The spelling of 49245591371 in words is "forty-nine billion, two hundred forty-five million, five hundred ninety-one thousand, three hundred seventy-one".
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